4x^2-35x=50

Solution for 4x^2-35x=50 equation:

4x^2-35x=50

We move all terms to the left:

4x^2-35x-(50)=0

a = 4; b = -35; c = -50;
Δ = b2-4ac
Δ = -352-4·4·(-50)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-45}{2*4}=\frac{-10}{8}
=-1+1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+45}{2*4}=\frac{80}{8}
=10
$